Tuesday, July 8, 2025

7/8/2025 2011 AMC 12B H reflection notes

Q16 → Wrong due to silly mistake

Skipped Q20

  • Time-sink solution requires heavy observation and quick identification.
  • Involves quick use of inscribed angles and arcs.

Q25 → Not enough time

Was not able to solve; did not understand substitution of
n → n-k in the solution + solution video.
Redo!

Q24 Notes:

  • Easy algebra but looked difficult at first.
  • Just required extra time to complete — able to solve afterwards.

Q15, Q17, Q18, Q19, Q21, Q22, Q23 → Correct

  • Q17: Online solution took a long time
    • I had the fastest solution : the solution was first finding g(f(x)) = 10x-1, then subbing in the 1 to get h_1(1)=9, then continuously subbing 9 back into 10x-1 so it becomes 9, 89, 899, 8999….
  • Q19: Took a long time
    • Found faster solution but took time to get to it: this was a least upper bound question for the slope which hits the next lattice point. If I had the answers, it would have been easier to substitute them back into and find which one would work, but I had hidden the answers. What I did next was find a few of the closest points to 102, 50 which the slope would first intersect and the slope would be as close to 1/2 as possible. After testing a few values in the form of (n/1)/(2n+1) and (n+1)/(2n) which give values close to 1/2, 50/99 was the least of these.

Expected Value Question : 2024 Mathcounts State Sprint #24 level 1.5

Problem. Dennis rolls three fair six-sided dice, obtaining a, b, c ∈ {1,…,6}. Find \[ \mathbb{E}\!\bigl[\,|a-b|+|b-c|+|c-a|\,\bigr]. \]


Try the question first before scrolling down to read the solution. 


















Solution.

Step 1 — Linearity of expectation.

\[ \mathbb{E}\!\bigl[\,|a-b|+|b-c|+|c-a|\,\bigr] \;=\; \mathbb{E}[|a-b|]+\mathbb{E}[|b-c|]+\mathbb{E}[|c-a|] \;=\; 3\,\mathbb{E}[|a-b|]. \]

Step 2 — Expected absolute difference of two dice.

Let \(X = |a-b|\). Its distribution is

\[ \begin{array}{c|cccccc} d & 0 & 1 & 2 & 3 & 4 & 5 \\ \hline \Pr(X=d) & \tfrac{6}{36} & \tfrac{10}{36} & \tfrac{8}{36} & \tfrac{6}{36} & \tfrac{4}{36} & \tfrac{2}{36} \end{array} \] \[ \mathbb{E}[|a-b|] =\frac{1}{36}\bigl(0\cdot6 + 1\cdot10 + 2\cdot8 + 3\cdot6 + 4\cdot4 + 5\cdot2\bigr) =\frac{70}{36} =\frac{35}{18}. \]

Step 3 — Final answer.

\[ \mathbb{E}\!\bigl[\,|a-b|+|b-c|+|c-a|\,\bigr] = 3 \times \frac{35}{18} = \boxed{\tfrac{35}{6}}. \]

Friday, July 4, 2025

Ay reflection notes

Ay

 5/7 

1) Reviewed the attached problems and solutions and I understand them well
2) Attempted the 2024 AMC 12A in 60 minutes. I attempted #1 to #19 and got them all correct.
I had a headache after that so I couldn't attempt the rest of the questions. Skipped  -#20 to #25
Not sure how many I could have actually done.


7/4
1) Reviewed the attached problems and solutions 
2) Attempted the SAT Reading and Writing test 6

Module 1: I was able to do 29 questions in 32 minutes.
Out of the first 29 that I attempted, I got these wrong- 4, 5, 15, 18 and 29
Rest correct

Module 2:  I kind of rushed for this module and attempted all 33 questions but got a lot of incorrect answers
Incorrect 4,5,9,10,12,21-26 and 33
and rest correct


Saturday, June 28, 2025

Ar. Student reflection notes to keep track of progress

 from a 9th grader Ar. 

Hello Mrs. Lin, 4/25

I hope you are well.
Sorry for sending this a bit late, but I wanted to share my reflection for what I have done this week. I first looked over the problems we did in class. I had some issue with the last problem-I am still not 100 percent on that one. I was hoping if you could please re-explain this in class, that would be helpful. I also looked over the formula sheet. While doing some of the AMC problems you gave, I tried to really focus on the first 7 problems. I was hoping we could go over some quicker ways to think on problems 3, 5, and 6 on the AMC 10 2023 A.
Sorry for sending this late.
Thank you,

Thank you Mrs. Lin. 5/2
I wanted to share my reflection for this week. I reviewed all of the problems we went through during class, and I really understood everything. I continued doing problems from the AMC 10 2023 A test, and I redid problems 3, 5, 7. Those were the problems I struggled with last week, so I reviewed those. I also tried to go on by doing problems 7 to 13, but it took me a while to do those and I didn’t get those correct. I went back to problems 1 through 7, except for the B test.
Thank you,


Hello Mrs. Lin, 5/11
I wanted to share my reflection from this week.
I felt good about all the problems we did in class, but I wanted to just quickly go over the last problem once more. I had a question on that one. I started a new test (2022 AMC 10 A), and did questions 1-10. I was hoping to go over questions 5, 7, 8, and 10. 

5/17 no notes 

5/24

This week I reviewed the SAT problems we went over in class. If you could please give me some of those harder SAT problems going forward for homework that would be great. I thought that they were good practice. 


I didn’t have a ton of time this week for AMC work, because I have finals for many classes coming up. However, I did do some problems from the 2016 AMC 10 A. 

I had some trouble with problems 11, 12 and 9. If we could please go over those that would be great Sorry about the late reflection again.


5/31
Hi Mrs. Lin,
I wanted to send you my reflection for this week. I re-did the AMC 10 2016 A test, including the problems from last week. I also did problems 13 to 20. I had questions on 13, 17, 18, and 20.
Thanks,

6/28 
Hello Mrs. Lin,
I hope you are doing well.
This week, I redid the problems from last class, and reviewed the formula sheet on geometry. I worked on problems 1-15 on the AMC 10 A from 2017. I had some trouble with questions 9, 12, and 15. 
Talk soon,


7/5/2025
Hi Mrs. Lin,
This week, I worked on the problems that we went over in class. Additionally, I worked on AMC 10 problems from the aops website from the 2021 spring AMC 10 A test. I wanted to go over problems 12, 13, 15, and 16.
Talk soon,

Monday, June 23, 2025

H. a 10th grader student reflection notes

 6/17/2025 2010 AMC 12A




 









6/24/2025  
2010 AMC 12 B