Note that:
(x+y)2−2xy=x2+y2
(x−y)2+2xy=x2+y2
(x−y)3+3xy(x−y)=x3−y3
(x+y)3−3xy(x+y)=x3+y3
(x+y+z)2−2(xy+yz+xz)=x2+y2+z2
Applicable questions:
Question 1: If x + y = a and xy = b, what is the sum of the reciprocals of x and y?
Solution:
1x+1y=x+yxy= ab
Question 2: If x2+y2=153 and x + y = 15, what is xy?
Solution:
(x+y)2−2xy=x2+y2
152−2xy=153→xy=36
Question 3: If (x+y)2=1024 , x2+y2 = 530 and x > y , what is x - y?
Solution:
(x+y)2−2xy=x2+y2
1024 - 2xy = 530→2xy=494
(x−y)2+2xy=x2+y2
(x−y)2=36
x - y = 6
Question 4: x + y = 3 and x2+y2=89, what is x3+y3?
Solution:
(x+y)2−2xy=x2+y2
9 - 2xy = 89 →−2xy=80 so xy = -40
(x+y)3−3xy(x+y)=27−3(−40)∗3=27+3∗40∗3=x3+y3
x3+y3= 387
Question #5: If x+1x=5, what is x3+1x3?
Solution:
(x+1x)3=x3+3x2.1x+3x.1x2+1x3
53=x3+3(x+1x)+1x3
125 - 3*5 = x3+1x3
The answer is 110.
Question #6 : 2011 Mathcounts state sprint #24 : x + y + z = 7 and x2+y2+z2=19, what is the arithmetic mean of the three
product xy + yz + xz?
Solution:
(x+y+z)2−2(xy+yz+xz)=x2+y2+z2
72−2(xy+yz+xz)=19
xy + yz + xz = 15 so their mean is 153=5
More practice problems (answer key below):
#1:If x + y = 5 and xy = 3, find the value of 1x2+1y2.
#2: If x + y = 3 and x2+y2=6, what is the value of x3+y3?
#3: The sum of two numbers is 2. The product of the same two numbers is 5.
Find the sum of the reciprocals of these two numbers, and express it in simplest form.
#4:If x−6x = 11, find the value of x3−216x3?
#5: If x+3x=9, find the value of x3+27x3?
#6:If x+1x=8, what is x3+1x3?
Answers:
#1 :199
#2: 13.5
#3: 25
#4: 1529 [ 113+ 3 x 6 x 11 =1529]
#5: 648 [93-3 x 3 x 9 = 648]
#6: 488 [ 83– 3 x 8 = 488]
Wednesday, July 6, 2016
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