Showing posts with label H. Show all posts
Showing posts with label H. Show all posts

Saturday, July 12, 2025

7/12/2025 2011 AMC 12A H reflection notes

2012 AMC 12 A Reflection Notes

Correct Answers: Questions 15–21

  • Questions: 15, 16, 17, 18, 19, 20, 21
  • Note on #16: Took time on one question using the Law of Cosines

Unanswered but Attempted: Questions 22, 23

  • Q22 & Q23:
    • Able to solve with help from solution
    • Need to improve:
      • Organized counting of objects
      • 3D visualization skills
  • Q23 Additional Note:
    • Not able to solve during the test
    • Watched a video solution afterward—it made sense, but I wouldn’t have made that connection under time pressure

Unanswered: Questions 24, 25

  • Q24:
    • Not able to compare exponents correctly
    • Had to look at the solution to understand
    • It was a complicated question
  • Q25:
    • Unable to solve even after reviewing the solution
    • Gaps in understanding—don’t think I could have arrived at that solution myself
    • Struggled with 3D visualization and drawing the necessary graph

Tuesday, July 8, 2025

7/8/2025 2011 AMC 12B H reflection notes

Q16 → Wrong due to silly mistake

Skipped Q20

  • Time-sink solution requires heavy observation and quick identification.
  • Involves quick use of inscribed angles and arcs.

Q25 → Not enough time

Was not able to solve; did not understand substitution of
n → n-k in the solution + solution video.
Redo!

Q24 Notes:

  • Easy algebra but looked difficult at first.
  • Just required extra time to complete — able to solve afterwards.

Q15, Q17, Q18, Q19, Q21, Q22, Q23 → Correct

  • Q17: Online solution took a long time
    • I had the fastest solution : the solution was first finding g(f(x)) = 10x-1, then subbing in the 1 to get h_1(1)=9, then continuously subbing 9 back into 10x-1 so it becomes 9, 89, 899, 8999….
  • Q19: Took a long time
    • Found faster solution but took time to get to it: this was a least upper bound question for the slope which hits the next lattice point. If I had the answers, it would have been easier to substitute them back into and find which one would work, but I had hidden the answers. What I did next was find a few of the closest points to 102, 50 which the slope would first intersect and the slope would be as close to 1/2 as possible. After testing a few values in the form of (n/1)/(2n+1) and (n+1)/(2n) which give values close to 1/2, 50/99 was the least of these.

Monday, June 23, 2025

H. a 10th grader student reflection notes

 6/17/2025 2010 AMC 12A




 









6/24/2025  
2010 AMC 12 B