Friday, May 25, 2012

Special Right Triangles: 30-60-90 and 45-45-90 Degrees Right Triangles





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Thanks a lot!!  Mrs. Lin







These are the two most common right triangles.

For 45-45-90 degrees, the ratio is  1 - 1 - √ 2

For 30-60-90 degrees, the ratio is  1 - √ 3 - 2

Other concepts to remember are that in any triangle a. larger angle corresponds to longer side and b.same 
angles have the same side length.

Level 0 skills check practices: 

Find the missing side length (answers below)

I: 45-45-90 degrees right triangle

a. 3 - ___- ___            b. 5 - ___- ___         c.   2 - ___ - ___      d. tricky : ___ - ___ - 3

e. ___ - ___ - 4           f. ___ - ___ - 6

II. 30-60-90 degrees right triangle

a. 3 - ___- ___            b.  ___- ___  - 4        c.   2 - ___ - ___      d. ___ - ___ - 5

e.  ___ - 6 - ___           f. ___ - 3 - ___

Answer key and some notes:

I: 45-45-90 degrees right triangle

a. 3 - 3- 3  2              b. 5 - 5 - 5  2         c.   2 -  2  - 2       d. 6 /2 - 6 /2 - √3

e. 2√ 2 - 2√ 2 - 4         f. 3 2 - 3√ 2  - 6

Notes:
a. Given the side length to 45 degrees, the easiest way to get the 90 degree side length is to time that number by  2 .

b. Given the side length to 90 degrees, the easiest way to get the 45 degree side length is to divide that number by 2 and then times  2 .

II. 30-60-90 degrees right triangle

a. 3 - 33 - 6            b.  2 - 2√3 - 4        c.   2 6  - 2√ 2       d. 2.5 - 2.53 - 5

e.  2√3 - 6 - 4√3         f.  3 - 3 -  2√3

Notes:
a. Given the side length to 30 degrees, the easiest way to get 90 degrees side length is to times 2 to the 30 degree side length. To get the side length to 60 degrees, times 3 to the side length to 30 degrees.

 b. Given the side length to 90 degrees, divide 90 degree side length by 2 to get the side length to 30 degrees.Times 3 to the side length of 30 degrees to get the side length of 60 degrees.

c. Given the side length to 60  degrees, divide that number by 3 and then times 3  to get the side length of 30 degrees. Times 2 to get the side length of 90 degrees.


Saturday, May 19, 2012

How Many Numbers (Terms)? Space, Inclusive and Exclusive Notes

Please write a comment and give me feedback. Thanks a lot!!

Quite a lot of my students have problems figuring out this type of problems so here are the notes.

#1: How many consecutive numbers from 1 to 5 inclusive?

1 _ 2 _ 3 _ 4 _ 5   There are 5 numbers if you just list them and count them out; however, what if
the question is:

#2: How many consecutive numbers from 34 to 200 (SAT type problem)?

Most students would think it's 200 - 34 = 166, but it's not.

Using #1 case, if you do 5 - 1 = 4, you are only getting how many spaces between those consecutive numbers.

Thus for question #2, the correct answer is 200 - 34 + 1 or 200 - 33 = 167

#3: What about how many consecutive numbers from 5 to 100 exclusive?

Inclusive means including the first and the last numbers; exclusive means not including the first and the last numbers, so for this question, you do 100 - 5 - 1 = 94.

Use # 1 case to help you figure out and really understand the concepts involved.

Here are other questions to help you practice the skills.

Word problems:  Answers below.

#1: How many numbers from 45 to 100 inclusive? 
#2: How many numbers from 17 to 127 inclusive? 
#3: How many numbers from 12 to 34 exclusive? 
#4: How many multiples of 9 from 1 to 200 inclusive?




#5: The dimension of the square on the left is 20 feet by 20 feet. If you  place a post every four feet, starting at one corner, how many posts will be placed? 






#6:  The distance from exit 13 to 21 is 216 miles. How many miles is the distance between two exits if all exits are equally spaced? 

#7: How many multiples of 5 from 120 to 218 exclusive? 

#8: Who is right? The teacher or the student?  Try this question.

#9: How many numbers from -12, -11, -10.........56 inclusive? 
What is their sum?

#10: How many numbers are in the list: 17.25, 18.25, 19, 25...111.25? 














Solutions: To excel at Mathcounts state/national, you need to practice all these questions mentally.

#1: 100 - 45 + 1 = 100 - 44 = 56
#2: 127-17 + 1 = 127 - 16 = 111
#3: Exclusive: 34 -12 -1 = 34 - 13 = 21
#4: Multiples of 9 from 1 to 200 starts with 9 and ends in 198.

Solution I: 9 , 18, 27...198  = 9 (1, 2, 3, ...22) The answer is 22.

Solution II:   \(\frac{(198 - 9)}{9} + 1 = 22"\)




#5:  Just observe one side first. Exclude the 4 corners, the other posts
are similar to those exclusive type problems.
There are \frac{20}{4} - 1 = 4 posts on each side so 4 * 4 + 4 (corner posts)
= 20



 #6: There are 21 - 13 = 8 space so\frac{216}{8} = 27 miles.  The answer is 27 miles.
#7:  Multiples of 5 from 120 to 218 start with 120 and end in 215.
Since it's asking exclusive, 120, 125, ...215 = 5(24, 25, ...43)
43 - 24 - 1 = 43 - 25 = 18
#8: You only need two cuts to get 3 pieces so 2 * 10 = 20 minutes. The student is right.
#9: 56 - ( -12) + 1 = 56 + 13 = 69
The sum is from 13 to 56 since up to 12 it got cancelled with the negative equivalent numbers.
Use average * the term you got  \frac{(13 + 56)}{2}* (56 - 13 +1) = 1518. The sum is 1518.
#10:111.25 - 117.25 + 1 = 111.25 - 116.25 = 95

Friday, May 11, 2012

Problem Solving Strategy: Probability, Counting, Grid

Check out Mathcounts here, the best competition math program for middle school students.
Download this year's Mathcounts handbook here. (It's free.)


#5 1993 Mathcounts National Target : Find the probability that four randomly selected points on the geoboard below will be the vertices of a square? Express your answer as a common fraction.












#5 2004 AMC 10A: A set of three points is chosen randomly from the grid shown. Each three-point set has the same probability of being chosen. What is the probability that the points lie on the same straight line?























Solution:
#5 National Target: There are 16C4 = (16 x 15 x 14 x 13)/ 4 x 3 x 2 = 1820 ways to select 4 points on the geoboard.

There are 3 x 3 = 9  one by one squares and 2 x 2 = 4 two by two squares and 1 x 1 = 1 three by three squares. (Do you see the pattern?)
                                                         

There are 4 other squares that have side length of √ 2
and 2 other larger squares that have side length of 5.

9 + 4 + 1 + 4 + 2 = 20 and 20/1820 = 1/91





#5 AMC-10A: There are 9C3 = (9 x 8 x 7) / 3 x 2 x 1 = 84 ways to chose the three dots and 8 of the lines connecting the three dots will form straight lines. (Three verticals, three horizontals and two diagonals.) so 
8/84 = 2/21

Problem Solving Strategy: Counting Coins

Q: How many ways can you make 25 cents if you can use quarters, dimes, nickels or pennies?
Start with the largest value:

1 Quarter      1 way

2 Dimes, 1 Nickel   You can stop here since it implies 2 ways.
2 Dimes, 0 Nickel ( which implies 5 pennies)

1 Dime, 3 Nickels , which implies 4 ways.
1 Dime, 2 Nickels ( 5 pennies)
1 Dime, 1 Nickel   (10 pennies)
1 Dime, 0 Nickel ( 15 pennies)

0 Dime, 5 N, which implies 6 ways.
: , 4 N  (5 pennies)
: , 3 N  (10 pennies)
: , 2 N  (15 pennies)
: , 1 N  (20 pennies)
: , 0 N (25 pennies)

So altogether 13 ways.

Practice questions: (answers below)

Q 1 : How many ways can you make a. 15cents, b. 20cents, c. 30 cents if you can use quarters, dimes, nickels or pennies?

Q 2 : How many different combination of coins could a person have if she has exactly 21 cents?

Q 3 :Using nickels, dimes, quarters and/or half-dollars, how many ways can you make 75 cents?

Q 4: 20 coins of quarters and nickels add up to 4 dollars. How many nickels are there? 


Q5:  What is the least number of US coins to make changes possible from 1 to  99 cents inclusive? (half dollar is allowed)










Answers: 


#1: a. 6 ways ; b. 9 ways; c 18 ways ;
#2: 9 ways
#3: 22  ways
#4: 5 nickels and 15 quarters   
#5: 9 coins (1 half dollar, 1 quarter, 2 dimes, 1 nickel and 4 pennies)

Wednesday, May 9, 2012

Prime Numbers: Mathcounts Beginning Level

This year's Mathcounts' handbook can be downloaded free here .

Please take a look at what that program is all about. It's team work, problem solving, fun, friendship building and lots and lots more. The majority of students we met at the Mathcounts Nationals all went to the most selected colleges and are thriving there.

Useful Definitions:

Prime – a number which cannot be divided by any numbers other than 1 and itself.

Factors – all whole numbers which can evenly divide a given number

Factoring – the breakdown of any number into its prime components

Greatest Common Factor (GCF)– the greatest number which is a factor of two or more given numbers

Least Common Multiple/Denominator (LCM)– the smallest number which is a multiple of two or more given numbers

Relatively Prime – two numbers with a GCF of 1

A prime, as stated in the list of useful definitions, is a number which cannot be divided by any numbers other than 1 and itself. The smallest prime is 2. [Or, as some people claim, the oddest prime.]

Whole numbers which are not primes are called composite. The smallest composite number is 4.

1 is the exception: it is considered to be neither a prime nor a composite number.

Given a chart of the whole numbers 2-100, the primes can be easily recognized:
The easiest thing to do is to the look at the smallest primes – namely, 2, 3, 5, 7 – and cross all multiples of them from the chart. 

The numbers most commonly mistaken for primes are 51, 57 and 91. The first two (51 and 57) as can be shown by adding up the digits, is divisible by 3, while 91 is equal to 7x13. 

To decide whether or not a number is a prime, take its square root and try dividing the original number by all primes less than the square root. If it is not divisible by any of them, the number is a prime. 

Questions: (beginning level) 

#1: List all the two digit prime numbers that end in a. unit digit 1. b. unit digit 3. c. unit digit 7. d. unit digit 9.

#2: What is the smallest prime number that is the sum of two prime square numbers? 

#3: An emirp (prime spelled backwards) is a prime that gives you a different prime when its digits are reversed. What is the smallest emirp? What are all of the emirps between 1 and 100 inclusive?

#4: The number "p" has three distinct prime factors. How many factors does the number "p" have?

#5: What is the smallest number that has 5 factors? 7 factors? 11 factors? Any pattern?

#6: What is the smallest number that has 6 factors? 10 factors? 12 factors? 20 factors?

#7: How many positive factors does the number 24 have?

#8: Find the sum of all the positive factors of 24?

#9: The GCF (greatest common factor) of x and 21 is "3". If x is smaller than 200, how many possible x are there?

#10: How many even factors does the number 180 have?

Solutions:

#1: See the prime number chart.

#2:  22 + 32 = 13

#3:  13 ( 31 is the reverse prime). The other emirps below 100 are 17, 31, 37, 71, 73, 79, and 97.

#4:  To fine how many factors a number has, you prime factorize that number and add one to each of the
exponents of those prime and multiply them together.
Let x, y, z be the three prime numbers that make up the number p.
p = x * y * z  (1 + 1) (1 + 1) (1 + 1) = 8 -- each prime number has exponent 1.
The 8 factors of p are 1, x, y, z, xy, xz, yz, xyz (or p)

#5: The smallest number that has 5 factors is 24 or 16. The factors are 1, 2, 4, 8, 16.
Since the exponent is 4, there are (4 + 1) = 5 factors.
The smallest number that has 7 factors is 26 or 64.
The smallest number that has 11 factors is 210 = 1024
5, 7, 11 are all prime numbers. 

#6: This one is harder than the previous question. 6 =1*6 or 3 * 2
25 = 32  ;   22 * 3 = 12  (both numbers have 6 factors but the latter is much smaller).
The answer is 12.

10 = 1 x 10 = 5 x 2  ;  24 * 3 = 48

12 = 1 x 12 = 6 x 2 = 4 x 3 = 3 x 2 x 2
22* 3 * 5 = 60

20 = 1 x 20 = 2 x 10 = 5 x 2 x 2
24* 3 * 5 = 240

#7: 24 = 31*23 (1 + 1) (3+1) =8; Those factors are:














#8: Continue to the previous number 24, the easiest way to find the sum is to use the
following method:
(1 + 2 + 4 + 8) (1 + 3) = 60

#9: 
#10:  180 = 22* 3 2* 5
To get just the even factors, you need to keep a 2 to guarantee the factors stay even.
2 ( 2 * 32* 5)  There are (1+1)(2+1)(1+1) = 12 factors.