From Mathcounts Mini : Video tutorials on counting and probability for Mathcounts state prep
Counting the Number of Subsets of a Set
Constructive Counting
More Constructive Counting
Probability and Counting
Probability with Geometry Representations : Oh dear, the second half part is hilarious.
Probability with Geometry Representations : solution to the second half problem from previous video
Try this one from 1998 AIME #9. It's not too bad.
Monday, January 6, 2014
Thursday, December 12, 2013
2014 Mathcounts State Prep : Folding Paper Questions
Folding paper questions are not too bad so here are two examples:
Question #1: The two side lengths of rectangle ABCD is "a" and "b". If you fold along EF and the point B now converges on point D, what is the length of \(\overline {EF}\)?
Solution I :
Let the length of \(\overline {FC}\) be x and the length of \(\overline {FD}\) is thus a - x.
Using Pythagorean theorem you'll easily get x (the \( x^{2}\) part cancel each other out) and from there get the length of a - x.
\(\overline {HD}\) = \(\dfrac {1} {2}\) of the hypotenuse. (Use Pythagorean theorem or Pythagorean triples to get that length,)
Again, using Pythagorean theorem you'll get the length of \(\overline {HF}\). Times 2 to get \(\overline {EF}\).
Solution II :
After you find the length of x, use \(\overline {EG}\), which is a - 2x and b as two legs of the right triangle EGF, you can easily get \(\overline {EF}\). (Pythagorean theorem)
Question #2:
What about this time you fold B to touch the other side.
What is the length of EF?
This one is not too bad.
Do you see there are two similar triangles?
Just make sure you use the same corresponding sides to get the desired
length.
Question #1: The two side lengths of rectangle ABCD is "a" and "b". If you fold along EF and the point B now converges on point D, what is the length of \(\overline {EF}\)?
Solution I :
Let the length of \(\overline {FC}\) be x and the length of \(\overline {FD}\) is thus a - x.
Using Pythagorean theorem you'll easily get x (the \( x^{2}\) part cancel each other out) and from there get the length of a - x.
\(\overline {HD}\) = \(\dfrac {1} {2}\) of the hypotenuse. (Use Pythagorean theorem or Pythagorean triples to get that length,)
Again, using Pythagorean theorem you'll get the length of \(\overline {HF}\). Times 2 to get \(\overline {EF}\).
Solution II :
After you find the length of x, use \(\overline {EG}\), which is a - 2x and b as two legs of the right triangle EGF, you can easily get \(\overline {EF}\). (Pythagorean theorem)
Question #2:
What about this time you fold B to touch the other side.
What is the length of EF?
This one is not too bad.
Do you see there are two similar triangles?
Just make sure you use the same corresponding sides to get the desired
length.
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