mathcounts notes

The best math program for middle school students

Wednesday, July 4, 2012

Similar Triangles II

$\frac{AD}{BD}$ = $\frac{CD}{AD}$

$\textcolor{red}{AD^2 = BD * CD}$

$\frac{AB}{BC}$ = $\frac{DB}{AB}$

$\textcolor{red}{AB^2 = BD * BC}$

$\frac{AC}{BC}$ = $\frac{CD}{AC}$

$\textcolor{red}{AC^2 = CD * CB}$

someone opposite of Pierre at 9:39 AM No comments:

‹

›

Home

View web version

About Me

someone opposite of Pierre: Conducts online group lessons. Mentors inquisitive students across the states, guides and learns with them. Finds the best materials at the lowest costs to help students get a top-notch education. Main focus : Problem solving, critical thinking, SAT harder/hardest problems prep, independent projects, academic consultant (Find the better fit.) My best state/national level students push themselves, not the other way around.

View my complete profile

Powered by Blogger.