Wednesday, July 4, 2012

Similar Triangles II

\frac{AD}{BD} = \frac{CD}{AD}

 \textcolor{red}{AD^2 = BD * CD}
 
\frac{AB}{BC} = \frac{DB}{AB}

\textcolor{red}{AB^2 = BD * BC}

\frac{AC}{BC} = \frac{CD}{AC}

\textcolor{red}{AC^2 = CD * CB}



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